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(4x-1)(4x+1)-16x^2+3x=2
We move all terms to the left:
(4x-1)(4x+1)-16x^2+3x-(2)=0
We add all the numbers together, and all the variables
-16x^2+3x+(4x-1)(4x+1)-2=0
We use the square of the difference formula
-16x^2+16x^2+3x-1-2=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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